g^2+15g-8=4

Solution for g^2+15g-8=4 equation:

g^2+15g-8=4

We move all terms to the left:

g^2+15g-8-(4)=0

We add all the numbers together, and all the variables

g^2+15g-12=0

a = 1; b = 15; c = -12;
Δ = b2-4ac
Δ = 152-4·1·(-12)
Δ = 273
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{273}}{2*1}=\frac{-15-\sqrt{273}}{2}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{273}}{2*1}=\frac{-15+\sqrt{273}}{2}
$